Y=-0.95x^2+6.5x

Solution for Y=-0.95x^2+6.5x equation:

=-0.95Y^2+6.5Y

We move all terms to the left:

-(-0.95Y^2+6.5Y)=0

We get rid of parentheses

0.95Y^2-6.5Y=0

a = 0.95; b = -6.5; c = 0;
Δ = b2-4ac
Δ = -6.52-4·0.95·0
Δ = 42.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6.5)-\sqrt{42.25}}{2*0.95}=\frac{6.5-\sqrt{42.25}}{1.9}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6.5)+\sqrt{42.25}}{2*0.95}=\frac{6.5+\sqrt{42.25}}{1.9}
$